it ended up being all bleached with split ends, had to cut the ends a couple of inches, more than was needed. i highly recommend going to prive, and not to someone cheap. danica reviews up votes badges helpful? votes report review great service with a smile!...
it ended up being all bleached with split ends, had to cut the ends a couple of inches, more than was needed. i highly recommend going to prive, and not to someone cheap. danica reviews up votes badges helpful? votes report review great service with a smile!...
every $c > $ there is $m_ (c)$ such that for all $n \geq m \geq m_ (c)$, $$ t(m,n) < c(m + \log n). $$ this doesn't rule out an $o(\log n)$ algorithm, since $\log n$ doesn't satisfy the property written above. share | cite | improve this answer answered apr ' at : yuval filmus yuval filmus k gold badges...
problem, then we can solve the decision problem: just compare the value of the maximum cut to $k$. conversely, if we can solve the decision problem, we can solve the optimization problem, using binary search. share | cite | improve this answer answered dec ' at : yuval filmus yuval filmus k gold badges...
bronze badges \$\endgroup\$ \$egingroup\$ what what controls a mosfet is the voltage difference between the gate and source. not the voltage at the gate relative to ground because the mosfet cannot see the voltage at ground. how can it?...
silver badges bronze badges asked hours ago zhenshan jin zhenshan jin bronze badge new contributor zhenshan jin is a new contributor to this site. take care in asking for clarification, commenting, and answering. check out our code of conduct . welcome to tex.se!...
the closest english expression i could think of would be: "(to say two things) in the same breath". share | improve this answer answered hours ago l'électeur l'électeur k gold badges silver badges bronze badges for very clear explanation on the "immediate" part. it is exactly how it would fit, now...
of drywall. the corner bead will cover it all. if you wish after that, you could add a small piece of molding like quarter round at the inside corner of the corner bead and door jamb to help finish it out a little better. share | improve this answer answered hours ago jack jack k gold badge silver badges...
form: $$ r=r+a\sin(n heta) $$ or $$ r=r+a\cos(n heta) $$ that represent an oscillation around a circle of radius r with $n$ oscillations of amplitude $a$. see here for an exemple. share | cite | improve this answer edited may ' at : answered may ' at : emilio novati emilio novati . k gold badges silver...