votes $egingroup$ your solution is right. in fact, those rings are isomorphic as additive groups. they are different exactly when it comes to the monoid structure of multiplication, and your proof is correct. share | cite | improve this answer answered hours ago lucas henrique lucas henrique silver badges...
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the equivalence. the abstraction is a very clean specification what was taken into account in our tests and what was omitted. two model-based testing tools which can be recommended: microsoft spec explorer, conformiq designer share | cite | improve this answer answered hours ago goofy goofy bronze badges...
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