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logic share | cite | improve this question asked apr ' at : zeus zeus silver badges bronze badges $\endgroup$ $egingroup$ do we prefer classical logic? well, i'll be...didn't know that.
necessary; just because a logic doesn't exactly correspond how you think reality behaves is no count against its being interesting to think about, or its being useful as an approximation to or model of reality. share | cite | improve this answer answered apr ' at : zev chonoles zev chonoles k gold badges...
https://math.stackexchange.com/questions/348685/why-do-we-prefer-classical-logic-over-non-classical-logic
akorn badges - united kingdom business united kingdom business database home area & cities search akorn badges city/area: surrey country: united kingdom company profile akorn badges is a company at united kingdom,address is image house; a clifton road; kingston-upon-thames; surrey; kt ph address: image
house; a clifton road; kingston-upon-thames; surrey; kt ph city/area: surrey country: united kingdom category: badges and emblems employees: map this is google map of akorn badges address:image house; a clifton road; kingston-upon-thames; surrey; kt ph,surrey,united kingdom. if you find 'can not find...
http://m.uk.soopage.com/company/Akorn_Badges_3b.html
combinatorics permutations share | cite | improve this question edited hour ago n. f. taussig . k gold badges silver badges bronze badges asked hours ago dhanesh vijay dhanesh vijay bronze badges $\endgroup$ $egingroup$ please edit and use mathjax to properly format math expressions.
the girls $a,b,c,d$ to be consecutive. then we encounter the possibility: $$(a-b-c-d)-e-boys$$ where $e$ is the other girl. but if you have selected the girls $b,c,d,e$ we meet this possibility again in: $$a-(b-c-d-e)-boys$$ share | cite | improve this answer answered hour ago drhab drhab k gold badges...
https://math.stackexchange.com/questions/3545062/number-of-ways-in-which-5-boys-and-5-girls-can-stand-in-a-queue-such-that-ex
science-fiction medieval scientific-development share | improve this question edited hours ago frostfyre . k gold badges silver badges bronze badges asked hours ago user user bronze badges new contributor user is a new contributor to this site. take care in asking for clarification, commenting, and answering
share | improve this answer answered hours ago starfish prime starfish prime k gold badges silver badges bronze badges $\endgroup$ $egingroup$ thanks for the answer, would it be possible for you to link those questions to me?...
https://worldbuilding.stackexchange.com/questions/168295/which-is-easier-to-develop-a-piston-prop-engine-or-a-jet-engine
conic-sections plane-curves share | cite | improve this question edited hours ago narasimham . k gold badges silver badges bronze badges asked jan ' at : dominicr dominicr bronze badges $\endgroup$ $egingroup$ i suppose you are excluding degenerate conics where the plane of the section passes through
if its torsion $ au(t)$ vanishes for all $t$. but a straightforward calculation gives: $$ au(t)={ \over d}{\cotlpha \sin t \cos^ t}, $$ which vanishes only for $t= $. hence it cannot be a plane curve. share | cite | improve this answer edited jun ' at : answered apr ' at : aretino aretino . k gold badges...
https://math.stackexchange.com/questions/3082303/when-are-cone-geodesics-planar
number-theory share | cite | improve this question edited hours ago url silver badges bronze badges asked hours ago ellen ellen ellen ellen bronze badges $\endgroup$ $egingroup$ $y^ - x^ = $ is a pell equation $\endgroup$ – j. w. tanner hours ago $egingroup$ @almagest thank you, i am too trusting :)
pm $ then it is easy to check that $(m,n)=( m+ n, m+ n)$ is a solution to $y^ - x^ =\mp $. so given a solution $(m,n)$ to the original equation, $( m+ n, m+ n)$ is a larger solution. hence there are infinitely many. share | cite | improve this answer answered hours ago almagest almagest . k silver badges...
https://math.stackexchange.com/questions/3494364/prove-that-the-equation-has-infinitely-many-solutions-in-mathbbn2-x1
wordpress profiles register log in nick daugherty @nickdaugherty on wordpress.org and slack member since: march th, location: salida, colorado github: nickdaugherty job title: code wrangler employer: automattic find me on: bio code wrangler at wordpress.com vip contribution history nick daugherty's badges
wordpress profiles register log in nick daugherty @nickdaugherty on wordpress.org and slack member since: march th, location: salida, colorado github: nickdaugherty job title: code wrangler employer: automattic find me on: bio code wrangler at wordpress.com vip contribution history nick daugherty's badges...
https://profiles.wordpress.org/nickdaugherty/
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travel time map add to your site explore how far you can travel by car, bus, bike and foot from this location. nearby apartments walk score blog about how it works press terms & privacy feedback professional walk score widget walk score apis data services real estate professionals walkability research badges...
https://www.walkscore.com/score/Toronto
people of mathsstack are awesome..thanks each and everyone who are contribute their ideas here and who are helping to learn mathematics.. answers questions ~ k people reached india crackthesolution.com member for years, months profile views last seen mins ago communities ( ) mathematics k k silver badges
bronze badges tex - latex bronze badges computer science bronze badge mathematica bronze badge academia bronze badge view network profile → top network posts we respect a laser-like focus on one topic. top tags ( ) real-analysis score posts posts % ordinary-differential-equations score posts complex-analysis...
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questions tags users unanswered profile activity meta user network profile reputation windsheaf apparently, this user prefers to keep an air of mystery about them. answers questions ~ k people reached member for years, months profile views last seen mins ago communities ( ) mathematics . k . k silver badges
bronze badges mathoverflow silver badge bronze badges chess tex - latex top network posts is $\dim_k m/xm$ a multiple of $\dim_k r/xr$ for $m$ finitely generated, torsion-free $r$-module?...
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