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cows and chickens, the number of legs was more than twice the number of heads. the number of cows was: (a) , (b) , (c) , (d) , (e) solution: let the number of cows be x and their legs be x. let the number of chicken be y and their legs be x. total number of legs = x + y. total number of heads = x +
y. the number of legs was more than twice the number of heads. therefore, × (x + y) + = x + y. or, x + y + = x + y. or, x + = x [subtracting y from both sides]. or, = x – x [subtracting x from both sides]. or, = x. or, x = [dividing by on both sides]. therefore, the number of cows = . answer: (b) . the...
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